How do you solve $3Log_5 x - Log_5 4 = Log_5 16$ ?

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Answer 1 · 2016-06-15T07:18:10

$x=4$

$3log_5x-log_(5)4=log_(5)16$

or $log_5x^3-log_(5)4=log_(5)16$

or $log_5x^3/4=log_(5)16$

or $x^3/4=16$

or $x^3=64$

or $x=4$

How do you solve 3Log_5 x - Log_5 4 = Log_5 163Log_5 x - Log_5 4 = Log_5 16?