How do you solve (3n)/(n-1)+(6n-9)/(n-1)=6?

1 Answer

empty set

Explanation:

Add the two fractions as they have the same denominator.

(3n)/(n-1) + (6n-9) /(n-1) = (9n -9)/(n-1) = 9 ne 6

Now multiply both sides by (n-1)

{ (n-1) xx ( 9n-9)}/(n-1) = 6 xx ( n-1) This gives

(9n-9) = 6(n-1) the 9 can be factored out giving

9(n-1) = 6(n-1) now subtract 6(n-1) from both sides

9(n-1) - 6(n-1) = 6(n-1) - 6(n-1)

3 (n-1) = 0 distribute the 3 across the parenthesis

3n -3 = 0 add 3 to both sides.

3n -3 +3 = 0 +3

3n = 3 divide both sides by 3

(3n)/3 = 3/3 which gives

n = 1 But this value for n is forbidden, else you divide by zero