How do you solve $3x^2+5=5x^2+10$ ?

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Answer 1 · 2017-02-10T18:52:13

$x=+isqrt(5/2)$ and $x=-isqrt(5/2)$

Although this is under the section "completing the square," that is not what is required to solve this problem.

Step 1. Move everything to the left hand side

$3x^2-5x^2+5-10=0$

Step 2. Combine like terms

$-2x^2-5=0$

Step 3. Solve for $x$

$-2x^2-5=0$
$-2x^2=5$
$x^2=-5/2$
$x=+-isqrt(5/2)$

How do you solve 3x^2+5=5x^2+103x^2+5=5x^2+10?