How do you solve $3 x^{2} + 5 = 5 x^{2} + 10$ $3x^2+5=5x^2+10$ ?

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Answer 1 · 2017-02-10T18:52:13

$x = + i \sqrt{\frac{5}{2}}$ $x=+isqrt(5/2)$ and $x = - i \sqrt{\frac{5}{2}}$ $x=-isqrt(5/2)$

Although this is under the section "completing the square," that is not what is required to solve this problem.

Step 1. Move everything to the left hand side

$3 x^{2} - 5 x^{2} + 5 - 10 = 0$ $3x^2-5x^2+5-10=0$

Step 2. Combine like terms

$- 2 x^{2} - 5 = 0$ $-2x^2-5=0$

Step 3. Solve for $x$ $x$

$- 2 x^{2} - 5 = 0$ $-2x^2-5=0$
$- 2 x^{2} = 5$ $-2x^2=5$
$x^{2} = - \frac{5}{2}$ $x^2=-5/2$
$x = \pm i \sqrt{\frac{5}{2}}$ $x=+-isqrt(5/2)$

How do you solve 3x2+5=5x2+103x^2+5=5x^2+10?