How do you solve $3x - 2y = 0$ and $x + y = -5$ using substitution?

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Answer 1 · 2016-04-11T04:49:00

$x=-2$
$y=-3$

Given -

$3x-2y=0$ --------- (1)
$x+y=-5$ ------------(2)

Solve equation (2) for $x$

$y=-5-x$

Substitute $y=-5-x$ in equation (1)

$3x-2(-5-x)=0$
$3x+10+2x=0$
$5x=-10$
$x=-2$

Substitute $x=-2$ in equation (1)

$-2+y=-5$
$y=-5+2$
$y=-3$

How do you solve 3x - 2y = 03x - 2y = 0 and x + y = -5x + y = -5 using substitution?