How do you solve 3x+4y=2 and x-y+6?

1 Answer
Apr 18, 2018

This is presumably meant to be simple pair of linear simultaneous equations easily solved. The problem is the second one isn't equation; let's guess about what equation was meant:

3x + 4 y = 2

x - y = 6

Multiplying that equation by 4,

4x - 4 y = 24

Adding to the first equation,

7x = 26

x = 26 / 7

Multiplying the second equation by three:

3x - 3y = 18

Subtracting from the first,

7y = -16

y = - 16/7

Check:

x-y = 26/7 - -16/7 = 42/7 = 6 \quad \sqrt{}

3x + 4y = 1 7 (3(26) + 4(-16)) = 2 \quad \sqrt{}

Remember we had to guess the equation to start, so this might not be the exact problem the student is trying to answer.