How do you solve 3x + y = 7 and 3x - y = 5?

1 Answer
Jun 7, 2016

x = 2 " and " y = 1

Explanation:

There are 2 obvious methods which can be used in this example, based on the x and y values in the equations.

ELIMINATION METHOD
The two y terms are additive inverses. This means they have the same value, but opposite signs.
When they are ADDED together, they will make 0.

" " 3x + y = 7 " A"
" " 3x - y = 5 " B"

"A + B: " 6x " "= 12" (the y's have been eliminated)"
" " x" " = 2

Substitute into A to find the value of y:
" " 3(2) + y = 7
" " 6 + y = 7
" " y = 1

EQUATING METHOD

The two x-terms are exactly the same. Make the x term the subject.

3x + y = 7 " and " 3x - y = 5
3x " " = 7 - y " " 3x " "=5 + y

But 3x" is the same as "3x!!

Therefore " " 7 - y = 5 + y
solve for y: " " 7-5 = 2y
" " 2 = 2y " " rArr y = 1

If y = 1, substitute into either equation to find x.

3x = 7 - y rArr 3x = 7-1 = 6
3x = 6
x = 2