How do you solve $4^(-3t)=0.10$ ?

Question

2501 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-19T14:18:47

$4^(-3t)=0.10$

$4^(-3t)=0.10$
$ln(4^(-3t))=ln(0.10)$
$-3 t*ln(4)=ln(0.10)$
$t=- ln(0.10)/(3*ln(4))$

Answer 2 · 2018-05-19T14:19:30

$t=-log0.1/(3log4)~~0.55$

Given: $4^(-3t)=0.1$

Take logarithms on both sides.

$log(4^(-3t))=log0.1$

$=>-3tlog4=log0.1$

$=>-3t=log0.1/log4$

$t=-1/3log0.1/log4$

$t=-log0.1/(3log4)$

$~~0.55$

How do you solve 4^(-3t)=0.104^(-3t)=0.10?