How do you solve $- 4 (5^{x}) = - 68$ $-4(5^x)=-68$ ?

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How do you solve $- 4 (5^{x}) = - 68$ $-4(5^x)=-68$ ?

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Answer 1 · 2015-12-01T20:16:18

I found: $x = 1.76037$ $x=1.76037$

Explanation:

We can start rearranging our expression:
$5^{x} = \frac{- 68}{- 4}$ $5^x=(-68)/(-4)$

$5^{x} = 17$ $5^x=17$

take the natural log of both sides:

${ln 5}^{x} = ln 17$ $ln5^x=ln17$

use the property of logs: ${log x}^{a} = a log x$ $logx^a=alogx$ :
so:
$x ln 5 = ln 17$ $xln5=ln17$
so:
$x = \frac{ln (17)}{ln (5)} = 1.76037$ $x=ln(17)/ln(5)=1.76037$

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How do you solve $- 4 (5^{x}) = - 68$ $-4(5^x)=-68$ ?

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How do you solve $- 4 (5^{x}) = - 68$ $-4(5^x)=-68$ ?