How do you solve $4 log_12 2 + log_12 x = log_12 96$ ?

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Answer 1 · 2015-12-06T14:36:45

${6}$

Unite the logs.

$log_12 (2^4 * x) = log_12 96$

$A = B Rightarrow 12^A = 12^B$

$16 * x = 96$

$x = 6$

How do you solve 4 log_12 2 + log_12 x = log_12 96 4 log_12 2 + log_12 x = log_12 96?