How do you solve 4 Log_5 2 + Log_5 X = 3 Log_5 4 - Log_5 3? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Rui D. Dec 31, 2015 X=4/3 Explanation: 4*log_5 2+log_5 X=3*log_5 4-log_5 3 log_5 2^4+log_5 X=log_5 2^(2*3)-log_5 3 log_5 (2^4*X) = log_5 (2^6/3) 2^4.X=2^6/3 X=2^6/(2^4*3)=2^2/3=4/3 Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 2? How do you solve 2 log x^4 = 16? How do you solve 2+log_3(2x+5)-log_3x=4? See all questions in Logarithmic Models Impact of this question 3217 views around the world You can reuse this answer Creative Commons License