How do you solve 4 Log_5 2 + Log_5 X = 3 Log_5 4 - Log_5 3?

1 Answer
Dec 31, 2015

X=4/3

Explanation:

4*log_5 2+log_5 X=3*log_5 4-log_5 3
log_5 2^4+log_5 X=log_5 2^(2*3)-log_5 3
log_5 (2^4*X) = log_5 (2^6/3)
2^4.X=2^6/3
X=2^6/(2^4*3)=2^2/3=4/3