How do you solve $-4=log_5x$ ?

Question

1389 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-12-08T18:22:01

$x=1/625$

Consider $log_10 x=y -> 10^y=x$

Using the same concept for your question:

$log_5x=(-4) -> 5^(-4)=x$

so $x= 1/(5^4) =1/625$

How do you solve -4=log_5x-4=log_5x?