How do you solve $4^(x-1)=3$ ?

Question

1283 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-09-10T21:47:46

The value of $x=1+log3/log4$

Taking logarithms in both sides we get

$log4^(x-1)=log3=>(x-1)log4=log3=>x-1=log3/log4=>x=1+log3/log4$

How do you solve 4^(x-1)=34^(x-1)=3?