How do you solve $4^{x} \cdot 3^{2 x} = 6$ $4^x * 3^(2x) = 6$ ?

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How do you solve $4^{x} \cdot 3^{2 x} = 6$ $4^x * 3^(2x) = 6$ ?

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Answer 1 · 2016-04-16T00:55:12

$: . x = \frac{1}{2}$ $: . x=1/2$

Explanation:

$\Rightarrow {(4 \times 3^{2})}^{x} = 6 = 36^{\frac{1}{2}}$ $=>(4xx3^2)^x=6=36^(1/2)$
$\Rightarrow {(36)}^{x} = 36^{\frac{1}{2}}$ $=>(36)^x=36^(1/2)$
$: . x = \frac{1}{2}$ $: . x=1/2$

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How do you solve $4^{x} \cdot 3^{2 x} = 6$ $4^x * 3^(2x) = 6$ ?

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How do you solve $4^{x} \cdot 3^{2 x} = 6$ $4^x * 3^(2x) = 6$ ?