How do you solve $4^{x} - 3 = 5$ $4^x-3=5$ ?

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Answer 1 · 2016-07-20T09:37:46

$x = \frac{3}{2}$ $x=3/2$

First let's have the equivalent equation

$4^{x} = 8$ $4^x=8$

Then, since $4 = 2^{2} and 8 = 2^{3}$ $4=2^2 and 8=2^3$ , let's substitute:

$2^{2 x} = 2^{3}$ $2^(2x)=2^3$

so

$2 x = 3$ $2x=3$

$x = \frac{3}{2}$ $x=3/2$

How do you solve 4x−3=54^x-3=5?