How do you solve 4^x * 5^(4x+3) = 10^(2x+3)?
2 Answers
Explanation:
4^x*5^(4x+3)=10^(2x+3)
log(4^x*5^(4x+3))=log(10^(2x+3))
log(4^x)+log(5^(4x+3))=log(10^(2x+3))
xlog(4)+(4x+3)log(5)=(2x+3)log(10)
xlog(4)+4xlog(5)+3log(5)=2xlog(10)+3log(10)
xlog(4)+4xlog(5)-2xlog(10)=3log(10)-3log(5)
x(log(4)+4log(5)-2log(10))=3log(10)-3log(5)
x=(3log(10)-3log(5))/(log(4)+4log(5)-2log(10))
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Explanation:
Dividing both sides by
Taking
Dividing both sides by