How do you solve $4^(x + 7) = 6x – 1$ ?

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Answer 1 · 2015-09-12T14:18:47

There is no real solution.

I'm not sure how to explain it using precalculus ideas.

Here are the two functions on the same graph:

$f(x) = 4^(x+7)$ and $g(x) = 6x-1$

enter image source here

How do you solve 4^(x + 7) = 6x – 14^(x + 7) = 6x – 1?