How do you solve $4 cos (6 x) = \sqrt{12}$ $4cos(6x)=sqrt12$ ?

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Answer 1 · 2016-07-25T19:24:44

$x = \pm \frac{π}{36} + k \frac{π}{3}$ $x=+-pi/36+kpi/3$

First you can divide all terms by 4:

$cos (6 x) = \frac{\sqrt{12}}{4}$ $cos(6x)=sqrt(12)/4$

$cos (6 x) = \frac{\sqrt{3}}{2}$ $cos(6x)=sqrt(3)/2$

$6x=+-pi/6+2kpi, k=0,1,2,3,...$

$x=+-pi/36+kpi/3$

How do you solve 4cos(6x)=sqrt124cos(6x)=√124cos(6x)=sqrt12?