How do you solve $4 cos x = 2$ $4cosx=2$ ?

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Answer 1 · 2016-09-17T12:51:14

$x = 2 n π \pm \frac{π}{3}$ $x=2npi+-pi/3$

As $4 cos x = 2$ $4cosx=2$

$cos x = \frac{2}{4} = \frac{1}{2} = cos (\frac{π}{3})$ $cosx=2/4=1/2=cos(pi/3)$

As cosine is positive in first and fourth quadrant

$cos x = = cos (\pm \frac{π}{3})$ $cosx==cos(+-pi/3)$

and is a function with a cycle of $2 π$ $2pi$ .

$x = 2 n π \pm \frac{π}{3}$ $x=2npi+-pi/3$

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