How do you solve $4ln(2x+3)=11$ ?

Question

6678 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-14T11:54:15

$x=6.3213$

As $4ln(2x+3)=11$ ,

$ln(2x+3)=11/4=2.75$ or

$2x+3=e^(2.75)=15.6426$ or

$2x=15.6426-3=12.6426$ or

$x=12.6426/2=6.3213$

How do you solve 4ln(2x+3)=114ln(2x+3)=11?