How do you solve 4m+n=2 and m-4n=9 using substitution?

1 Answer
Apr 27, 2016

m=1" ; "n=-2

Explanation:

Given:
4m+n=2 -------------------------------Equation (1)
m-4n=9..........................................Equation (2)

color(blue)("Determine the value of n")

color(brown)("Showing every step in the first part to demonstrate method")

color(green)("Consider Equation (2)")

color(green)("Add 4n to both sides")

" "m-4n+4n=9+4n

color(green)("But "4n-4n=0)

" "m=9+4n .....................................(3)

color(green)("Substitute for m in (1) using (3)")

" "4m+n=2" "->" "4(9+4n)+n=2

color(green)("Multiply out the bracket")
" "=>36+16n+n=2

" "36+17n=2

color(green)("Subtract 36 from both sides")
" "17n=-34

color(green)("Divide both sides by 17")
" "color(blue)(n=-34/17=-2)
'.........................................................
color(blue)("Determine the value of m")

Substitute n=-2 into (2)

m-4n=9" "->" "m-4(-2)=9

m+8=9

m=9-8

m=1

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Check
4m+n=2" "->" "4(1)+(-2)=2
m-4n=9" "->" "1-4(-2)=9