How do you solve $4sin^2 x =1$ from pi to 2pi?

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Answer 1 · 2015-07-23T02:45:06

Solve $4sin^2 x = 1$ $(pi, 2pi)$
Ans: $(7pi)/6 and (11pi)/6$

$sin^2 x = 1/4$ --> $sin x = +- 1/2$

Within the interval $(pi, 2pi)$ , only the answer $(-1/2)$ is accepted.

$sin x = - 1/2$ --> $x = (7pi)/6$ and $x = (11pi)/6$

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