How do you solve $4sinx=2sinx+sqrt3$ ?

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Answer 1 · 2016-09-02T02:12:33

$x = 60^@$

$4sinx=2sinx+sqrt3$
$2sinx=sqrt3$
$sinx=sqrt3/2$

$x=60^@$

Answer 2 · 2016-09-04T07:53:09

$x = (pi) / (3)$

We have: $4 sin(x) = 2 sin(x) + sqrt(3)$

Let's subtract $2 sin(x)$ from both sides of the equation:

$=> 2 sin(x) = sqrt(3)$

Then, we can divide both sides by $2$ to get:

$=> sin(x)= (sqrt(3)) / (2)$

$=> x = (pi) / (3)$

Therefore, the solution to the equation is $x = (pi) / (3)$ .

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