Question

How do you solve `4tan3x+5=1` for `0<=x<=pi`?

Answer 1

The answer is `={pi/4,7/12pi,11/12pi}`

Explanation:

Let's simplify the equation

`4tan3x+5=1`

`4tan3x=-4`

`tan3x=-1`

`3x={3pi/4,7pi/4,11pi/4}`

`x={pi/4,7/12pi,11/12pi}`