How do you solve #4x^2=0# using the quadratic formula?

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Answer 1 · 2014-10-25T13:45:28

#x = (-b +- root2 (b^2 - 4ac))/(2a)#

Your equation

#4x^2 = 0#

can be re-written into

#4x^2 + 0x + 0 = 0#

Substituting the coefficients into the quadratic formula, we have

#x = (-b +- root2 (b^2 - 4ac))/(2a)#

#=> x = (-0 +- root2 (0^2 - 4(4)(0)))/(2(4))#

#=> x = (-0 +- root2 (0 - 0))/(8)#

#=> x = 0#