How do you solve $4x^2=0$ using the quadratic formula?

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Answer 1 · 2014-10-25T13:45:28

$x = (-b +- root2 (b^2 - 4ac))/(2a)$

Your equation

$4x^2 = 0$

can be re-written into

$4x^2 + 0x + 0 = 0$

Substituting the coefficients into the quadratic formula, we have

$x = (-b +- root2 (b^2 - 4ac))/(2a)$

$=> x = (-0 +- root2 (0^2 - 4(4)(0)))/(2(4))$

$=> x = (-0 +- root2 (0 - 0))/(8)$

$=> x = 0$

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