How do you solve #-4x^2+x+1=0# using the quadratic formula?

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Answer 1 · 2014-11-13T17:01:26

#-4x^2+x+1=0#

By comparing with

#ax^2+bx+c=0#,

we have

#{(a=-4),(b=1),(c=1):}#

#x={-b pm sqrt{b^2-4ac}}/{2a}#

#={-1 pm sqrt{1^2-4cdot(-4)cdot1}}/{2cdot(-4)}#

#={-1 pm sqrt{17}}/{-8}={1 pm sqrt{17}}/{8}#

Hence, the solutions are #x={1 pm sqrt{17}}/{8}#.

I hope that this was helpful.