How do you solve 4x^(2/3) - 5 = 20? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer José F. Apr 17, 2016 x=125/8 Explanation: 4x^(2/3)-5=20 4x^(2/3)=25 x^(2/3)=25/4 x=(25/4)^(3/2) x=(5^2/2^2)^(3/2) x=(5/2)^(3) x=125/8 Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 2? How do you solve 2 log x^4 = 16? How do you solve 2+log_3(2x+5)-log_3x=4? See all questions in Logarithmic Models Impact of this question 1412 views around the world You can reuse this answer Creative Commons License