Question

How do you solve `4x^2-4x+1>=0`?

Answer 1

This inequality holds for all `x in RR` since:

`4x^2-4x+1 = (2x-1)^2 >= 0`

Explanation:

You might recognise this perfect square trinomial, since:

`441 = 21^2`

So:

`4x^2-4x+1 = (2x-1)^2`