How do you solve $4 x + 7 y = 6$ $4x+7y=6$ and $6 x + 5 y = 20$ $6x+5y=20$ using elimination?

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Answer 1 · 2014-11-09T18:07:34

${(4x+7y=6),(6x+5y=20):}$

by multiplying the first equation by $3$ and the second equation by $2$ ,

$=>{(12x+21y=18),(12x+10y=40):}$

by subtracting the second equation from the first equation,

$=>11y=-22$

by dividing by $11$ ,

$=>y=-2$

By plugging $y=-2$ into the first equation of the original system,

$4x+7(-2)=6 => 4x-14=6$

by adding $14$ ,

$=> 4x=20$

by dividing by $4$ ,

$=> x=5$

Hence, the solution is $(x,y)=(5,-2)$ .

I hope that this was helpful.

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