Which method do you use to solve #x=3y# and #x-2y=-3#?
1 Answer
Nov 11, 2014
x = 3.y
x - 2y = -3 (a)
substitute x in the equation (a)
3y -2y = -3
y = -3
x = 3.y
x - 2y = -3 (a)
substitute x in the equation (a)
3y -2y = -3
y = -3