How do you solve $5 (1 + 10^{6} x) = 12$ $5(1+10^6x) = 12$ ?

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Answer 1 · 2015-10-18T12:26:48

Rearrange and take logs if necessary to find $x$ $x$ .

I'm not sure whether your question appears as intended, so I will answer both interpretations:

$5 (1 + 10^{6} x) = 12$ $bb (5(1+10^6x) = 12)$

Divide both sides by $5$ $5$ to get:

$1 + 10^{6} x = \frac{12}{5}$ $1+10^6x = 12/5$

Subtract $1$ $1$ from both sides to get:

$10^{6} x = \frac{7}{5}$ $10^6x = 7/5$

Divide both sides by $10^{6}$ $10^6$ to get:

$x = \frac{7}{5 \cdot 10^{6}} = 0.0000014$ $x = 7/(5*10^6) = 0.0000014$

$5 (1 + 10^{6 x}) = 12$ $bb (5(1+10^(6x)) = 12)$

Divide both sides by $5$ $5$ to get:

$1 + 10^{6 x} = \frac{12}{5}$ $1+10^(6x) = 12/5$

Subtract $1$ $1$ from both sides to get:

$10^{6 x} = \frac{7}{5}$ $10^(6x) = 7/5$

Take common logarithms of both sides to get:

$6 x = log (\frac{7}{5})$ $6x = log(7/5)$

Divide both sides by $6$ $6$ to get:

$x = \frac{log (\frac{7}{5})}{6} \approx 0.02435$ $x = log(7/5)/6 ~~ 0.02435$

How do you solve 5(1+106x)=125(1+10^6x) = 12?