How do you solve $5^(2x-1) = 7^(2x)$ ?

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Answer 1 · 2018-07-03T15:42:24

$x = frac{log 5}{2(log 5 - log 7)}$

$log 5^{2x - 1} = log 7^{2x}$

$(2x - 1) log 5 = 2x log 7$

$x (2 log 5 - 2 log 7) = 1 log 5$

$x = frac{log 5}{log 25 - log 49}$

$(25/49)^x = 5$

How do you solve 5^(2x-1) = 7^(2x)5^(2x-1) = 7^(2x)?