How do you solve $5^{2 x + 3} \leq 125$ $5^(2x+3)<=125$ ?

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Answer 1 · 2017-01-05T20:49:18

$x \leq 0$ $x<=0$

Since $125 = 5^{3}$ $125=5^3$ , the given inequality can be written as:

$5^{2 x + 3} \leq 5^{3}$ $5^(2x+3)<=5^3$

Then, since the base is less than 1, the inequality becomes:

$2x+cancel3<=cancel3$

that's

$2x<=0$

$x<=0$

How do you solve 5^(2x+3)<=12552x+3≤1255^(2x+3)<=125?