Question

How do you solve `5^(4-x)=1/5`?

Answer 1

For this kind of question i prefer not to use logarithm.
`5^(4-x)= 1/5`
Since we know that `1/5= 5^(-1)` [This is a rule; `1/a=a^-1`]
Than the equation will be;
`5^(4-x)=5^(-1)` Since 5 values are same we can write;
`4-x=-1 => 4+1=x => x=5`