How do you solve $5-log _ 6 (2x - 6) + log _ 6 x = 2$ ?

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Answer 1 · 2018-03-19T13:18:01

$5−log_6(2x−6)+log_6x=2$

$5-2=log_6(2x−6)-log_6x$

$3=log_6((2x−6)/x)$ [Since $color(red)(loga-logb = log(a/b)$ ]

$6^3 = ((2x−6)/x)$

$(2x−6)=216x$

$−6=214x$

$x=-3/107$

How do you solve 5-log _ 6 (2x - 6) + log _ 6 x = 25-log _ 6 (2x - 6) + log _ 6 x = 2?