Question

How do you solve `5^x+1=625`?

Answer 1

I found `x=3.999`

Explanation:

Write it as:
`5^x=625-1`
`5^x=624`
taking the log in base `5` on both sides:
`x=log_5(624)`
To find `x` we can try changing base and use a pocket calculator that can give us, say, the decimal log, as:
`x=log_5(624)=(log_10(624))/(log_10(5))=3.999`