How do you solve 5^x=17? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer ali ergin Mar 24, 2016 x=1,7603744273 Explanation: 5^x=17 log 5^x=log 17 x*log 5=log 17 log 5=0,6989700045 log 17=1,2304489214 x=(log 17)/(log 5) x=1,7603744273 Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 2? How do you solve 2 log x^4 = 16? How do you solve 2+log_3(2x+5)-log_3x=4? See all questions in Logarithmic Models Impact of this question 12993 views around the world You can reuse this answer Creative Commons License