How do you solve $(5-x)^2(x-13/2)<0$ ?

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Answer 1 · 2016-07-06T03:48:38

$x in (-oo,13/2)-{5}$

Observe that $AAx in RR, (5-x)^2>=0,$ equality holds $iff x=5.$

Hence, $(5-x)^2(x-13/2)<0 iff (x-13/2)<0 & x!=5 iff x<13/2, x!=5$ .

This can be put as $x in (-oo,13/2)-{5}$

How do you solve (5-x)^2(x-13/2)<0(5-x)^2(x-13/2)<0?