Question

How do you solve `5e^(2x+11)=30`?

Answer 1

I found `x=-4.6`

Explanation:

We can rearrange it as:
`e^(2x+11)=30/5`
`e^(2x+11)=6`
take the natural log of both sides:
`lne^(2x+11)=ln6`
giving:
`2x+11=ln6`
`2x=ln6-11`
`x=(ln6-11)/2=-4.6`