How do you solve $5log_10(x-2)=11$ ?

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Answer 1 · 2018-07-03T13:20:58

$color(blue)(x=10^(11/5)+2~~160.4893192)$

$5log_(10)(x-2)=11$

Divide by 5:

$log_(10)(x-2)=11/5$

Raising the base to these:

$10^(log_(10)(x-2))=10^(11/5)$

$x-2=10^(11/5$

$x=10^(11/5)+2~~160.4893192$

How do you solve 5log_10(x-2)=115log_10(x-2)=11?