How do you solve $5 q - 7 = \frac{2}{3}$ $5q - 7 = \frac{2}{3}$ ?

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Answer 1 · 2014-09-28T14:11:41

$5 q - 7 = \frac{2}{3}$ $5q -7 = 2/3$

Transposing 7,

$5 q = \frac{2}{3} + 7$ $5q = 2 /3 + 7$

$5 q = \frac{2 + 21}{3}$ $5q = (2 + 21 ) /3$

$5 q = \frac{23}{3}$ $5q = 23 / 3$

$5 q \cdot 3 = 23$ $5q * 3 = 23$

$15 q = 23$ $15 q = 23$

$q = \frac{23}{15}$ $q = 23 /15$

How do you solve 5q−7=235q - 7 = \frac{2}{3}?