How do you solve #5x – 2y = 10# and #y = 3x – 5# using substitution? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer Binayaka C. May 1, 2016 #x=0;y=-5# Explanation: Sustituting #y=3x-5# in the equation we get #5x-2(3x-5)=10 or 5x-6x+10=10 or -x=0 or x=0 :. y =3*0-5=-5#[Ans] Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 1634 views around the world You can reuse this answer Creative Commons License