How do you solve $5x-3y= 8$ and $-6x+y=20$ using substitution?

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Answer 1 · 2018-07-09T22:51:24

$x=-68/13$ & $y=-148/13$

Given equations:

$5x-3y=8\ .........(1)$

$-6x+y=20\ ...........(2)$

Substituting $y=6x+20$ from (2) into (1), we get

$5x-3(6x+20)=8$

$-13x-60=8$

$-13x=68$

$x=-68/13$

Substituting $x=-68/13$ in (2), we get

$y=6x+20$

$=6(-68/13)+20$

$=-\frac{148}{13}$

How do you solve 5x-3y= 85x-3y= 8 and -6x+y=20-6x+y=20 using substitution?