How do you solve $5x+y=5$ and $3x+2y=3$ using substitution?

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Answer 1 · 2018-04-21T19:24:20

$x=1 and y=2$

$" "5x+y+(−5x)=5+(−5x)" "$ (Add $-5x$ to both sides)

$" "y=−5x+5$ .

Substitute $color(blue)((−5x+5))$ for $color(blue)(y) " in " 3x+2y=3$ :

$" "3x+2color(blue)(y)=3$

$3x+2color(blue)((−5x+5))=3$

$3x-10x+10 =3$

$−7x+10=3$

$−7x+10+ (−10)=3+(−10)" "$ (Add $-10$ to both sides)

$−7x=−7$

$(7x)/-7=(-7)/-7" "$ (Divide both sides by $-7$ )

$x =1.$

Substitute $1$ for $x$ in $y=−5x+5$

$y=−5x+5$

$y=(−5)(1)+5$

$y=0" "$ (Simplify both sides of the equation).

How do you solve 5x+y=55x+y=5 and 3x+2y=33x+2y=3 using substitution?