Question

How do you solve `-6+ln(3x)=0`?

Answer 1

I found: `x=e^6/3`

Explanation:

We can start rearranging our expression:
`ln(3x)=6`
then use the definition of log to get (remembering that `ln` is the log in base `e`):
`3x=e^6`
so that:
`x=e^6/3`

or
`x=e^6/3=134.5`