First, we multiple each side of the equation by t(t + 2)# to eliminate the fractions and keep the equation balanced:
#tcolor(red)(cancel(color(black)((t + 2)))) xx 6/color(red)(cancel(color(black)((t + 2)))) = color(red)(cancel(color(black)(t)))(t + 2) xx 4/color(red)(cancel(color(black)(t)))#
#t xx 6 = (t + 2) xx 4#
#6t = 4t + 8#
Next, substract #color(red)(4t)# from each side of the equation to isolate the #t# term while keeping the equation balanced:
#6t - color(red)(4t) = 4t + 8 - color(red)(4t)#
#(6 - 4)t = 4t - color(red)(4t) + 8#
#2t = 0 + 8#
#2t = 8#
Now, divide each side of the equation by #color(red)(2)# to solve for #t#:
#(2t)/color(red)(2) = 8/color(red)(2)#
#(color(red)(cancel(color(black)(2)))t)/cancel(color(red)(2)) = 4#
#t = 4#