How do you solve $6 e^{9 x} = 1548$ $6e^(9x)=1548$ ?

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How do you solve $6 e^{9 x} = 1548$ $6e^(9x)=1548$ ?

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Answer 1 · 2016-02-05T15:57:40

I found $x = 0.617$ $x=0.617$

Explanation:

We can write it as:
$e^{9 x} = \frac{1548}{6}$ $e^(9x)=1548/6$
$e^{9 x} = 258$ $e^(9x)=258$
let us take the natural log of both sides:
$ln (e^{9 x}) = ln (258)$ $ln(e^(9x))=ln(258)$
$ln$ $ln$ and $e$ $e$ eliminate each othe and we get:
$9 x = ln (258)$ $9x=ln(258)$
$x = \frac{ln (258)}{9} = 0.617$ $x=(ln(258))/9=0.617$

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How do you solve $6 e^{9 x} = 1548$ $6e^(9x)=1548$ ?

1 Answer

Explanation:

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How do you solve $6 e^{9 x} = 1548$ $6e^(9x)=1548$ ?