Question

How do you solve `6x^2+5=2x^2+1`?

Answer 1

There is no real solution for `x`

Explanation:

Usually we would make a quadratic equation equal to 0.
However this example is a special case because there is no term in `x`

Re-arrange to give:

`6x^2 -2x^2 = 1-5`

`4x^2 = -4" " larr` alarm bells should start ringing!

`x^2 = -1`

This equation cannot be solved using real numbers because we cannot find the square root of a negative number.

To continue requires using complex numbers...