How do you solve #6x^2-5x+3=0#?
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1 Answer
May 23, 2015
y = 6x^2 - 5x + 3 = 0
D = d^2 = b^2 - 4ac = 25 - 72 = -47 < 0. There are no real roots, meaning the parabola graph doesn't intersect the x-axis.
There are 2 complex roots:
