How do you solve $7 - 2 e^{x} = 5$ $7 - 2 e ^ x = 5$ ?

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How do you solve $7 - 2 e^{x} = 5$ $7 - 2 e ^ x = 5$ ?

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Answer 1 · 2015-09-09T21:21:32

$x = 0$ $x=0$

Explanation:

Well it is $7 - 2 e^{x} = 5 \Rightarrow 7 - 5 = 2 e^{x} \Rightarrow 2 = 2 e^{x} \Rightarrow e^{x} = 1 \Rightarrow x = 0$ $7-2e^x=5=>7-5=2e^x=>2=2e^x=>e^x=1=>x=0$

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How do you solve $7 - 2 e^{x} = 5$ $7 - 2 e ^ x = 5$ ?

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