How do you solve 8=(1/4)^x?
1 Answer
May 20, 2018
Explanation:
"using the "color(blue)"laws of exponents"
•color(white)(x)a^mhArr1/a^m" and "(a^m)^n=a^(mn)
"left side "=8=2^3
"right side "=(1/4)^x=(1/2^2)^x=(2^-2)^x=2^((-2x))
rArr2^3=2^(-2x)larrcolor(blue)"equating both sides"
"since the bases on both sides are 2 equate the exponents"
rArr-2x=3rArrx=-3/2